Python实现的简单算术游戏实例

#!/usr/bin/env python
from operator import add, sub 
from random import randint, choice
ops = {'+': add, '-':sub}
#定义一个字典
MAXTRIES = 2 
def doprob():
 op = choice('+-')
 #用choice从'+-'中随意选择操作符 
 nums = [randint(1,10) for i in range(2)]
 #用randint(1,10)随机生成一个1到10的数,随机两次使用range(2) 
 nums.sort(reverse=True)
 #按升序排序
 ans = ops[op](*nums)
 #利用函数
 pr = '%d %s %d = ' % (nums[0], op, nums[1])
 oops = 0 
 #oops用来计算failure测试,当三次时自动给出答案
 while True:
 try:
 if int(raw_input(pr)) == ans:
 print 'correct'
 break
 if oops == MAXTRIES:
 print 'answer
 %s%d' % (pr, ans)
 break
 else:
 print 'incorrect... try again'
 oops += 1
 except (KeyboardInterrupt, EOFError, ValueError):
 print 'invalid ipnut... try again'
def main():
 while True:
 doprob()
 try:
 opt = raw_input('Again? [y]').lower()
 if opt and opt[0] == 'n':
 break
 except (KeyboardInterrupt, EOFError):
 break
if __name__ == '__main__':
 main()

运行结果如下：

8 - 1 = 7
correct
Again? [y]y
7 - 1 = 6
correct
Again? [y]y
9 + 4 = 0
incorrect... try again
9 + 4 = 

希望本文所述对大家的Python程序设计有所帮助。